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CREATE TABLE tbl_str_match_1 ( enumber int, ename varchar(100), eaddress varchar(500) ); INSERT INTO tbl_str_match_1 VALUES(1,'John Mak','Hno 12 Street Road, USA'); INSERT INTO tbl_str_match_1 VALUES(2,'Shai Lee','UK'); INSERT INTO tbl_str_match_1 VALUES(3,'Smith Watson','Street X01 UAE'); INSERT INTO tbl_str_match_1 VALUES(4,'Ray Gibbs','SA 124'); CREATE TABLE tbl_str_match_4 ( id INT IDENTITY(1,1), name varchar(100), [address] varchar(500) ); INSERT INTO tbl_str_match_4 VALUES('Mak John','Street Road, Hno 12, USA'); INSERT INTO tbl_str_match_4 VALUES('Shai Lee','UK'); INSERT INTO tbl_str_match_4 VALUES('A watson Smeeth ','UAE Street X01'); INSERT INTO tbl_str_match_4 VALUES('Henry Jay','RUS OP124'); DECLARE @enumber INT = 2 ;WITH c1 AS ( --To split the ename from first table SELECT s.value AS name FROM tbl_str_match_1 t CROSS APPLY STRING_SPLIT(t.ename, ' ') AS s WHERE enumber=@enumber ) ,c2 AS ( --To split the matching names from second table SELECT t.id,s.value AS name FROM tbl_str_match_4 t CROSS APPLY STRING_SPLIT(t.name, ' ') AS s WHERE EXISTS(SELECT 1 FROM c1 c WHERE t.name LIKE '%'+c.name+'%') ) ,c3 AS ( --To calculate the percentage of match SELECT id, CAST (COUNT(c1.name) AS FLOAT )/ CAST (COUNT(c2.name) AS FLOAT ) * 100 As Percentage FROM c2 LEFT JOIN c1 on c1.name =c2.name GROUP BY id ) --display the details SELECT t.*,c3.Percentage FROM tbl_str_match_4 t JOIN c3 ON t.Id=c3.Id
id
name
address
Percentage
2
Shai Lee
UK
100