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Developer-C 11.1
3.0
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CREATE TABLE orders ( customer_id NUMBER, order_total NUMBER, order_date DATE )
CREATE TABLE customers ( customer_id NUMBER, cust_first_name VARCHAR2(20), cust_last_name VARCHAR2(20), income_level NUMBER )
select o.customer_id, c.cust_first_name, c.cust_last_name, c.income_level, to_char(o.order_date, 'DD-MON-YY HH12:MI') as order_date, ROW_NUMBER() over (partition by o.customer_id order by o.order_date) as order#, o.order_total, lag(o.order_total, 1, 0) over (partition by o.customer_id order by o.customer_id) + lag(o.order_total, 2, 0) over (partition by o.customer_id order by o.customer_id) as last_two_orders_sum, min(o.order_date) keep (dense_rank last order by o.customer_id) as first_order_total from orders o, customers c where o.customer_id = c.customer_id
ORA-00937: not a single-group group function
select o.customer_id, c.cust_first_name, c.cust_last_name, c.income_level, to_char(o.order_date, 'DD-MON-YY HH12:MI') as order_date, ROW_NUMBER() over (partition by o.customer_id order by o.order_date) as order#, o.order_total, lag(o.order_total, 1, 0) over (partition by o.customer_id order by o.customer_id) + lag(o.order_total, 2, 0) over (partition by o.customer_id order by o.customer_id) as last_two_orders_sum, min(o.order_date) keep (dense_rank last order by o.customer_id) OVER () as first_order_total from orders o INNER JOIN customers c ON o.customer_id = c.customer_id
select o.customer_id, c.cust_first_name, c.cust_last_name, c.income_level, to_char(o.order_date, 'DD-MON-YY HH12:MI') as order_date, ROW_NUMBER() over (partition by o.customer_id order by o.order_date) as order#, o.order_total, lag(o.order_total, 1, 0) over (partition by o.customer_id order by o.customer_id) + lag(o.order_total, 2, 0) over (partition by o.customer_id order by o.customer_id) as last_two_orders_sum, MIN(o.order_date) OVER (PARTITION BY o.customer_id) as first_order_date, MIN(o.order_total) KEEP (DENSE_RANK FIRST ORDER BY o.order_date) OVER (PARTITION BY o.customer_id) as first_order_total from orders o INNER JOIN customers c ON o.customer_id = c.customer_id