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Developer-C 11.1
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CREATE TABLE `workPattern` ( `workpatternId` int(11) DEFAULT NULL, `Monday` text, `Tuesday` text, `Wednesday` text, `Thursday` text, `Friday` text, `Saturday` text, `Sunday` text ) ENGINE=InnoDB DEFAULT CHARSET=latin1; INSERT INTO `workPattern` (`workpatternId`, `Monday`, `Tuesday`, `Wednesday`, `Thursday`, `Friday`, `Saturday`, `Sunday`) VALUES (20, 'ALL', 'ALL', 'ALL', 'ALL', 'ALL', 'NULL', 'NULL'); Create table Employee ( `empId` int(11), `workpatternId` int(11) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; INSERT INTO Employee (`empId`, `workpatternId`) values (1,20); select sum(wp.`Monday`='ALL') + sum(wp.`Tuesday`='ALL') + sum(wp.`Wednesday`='ALL')+ sum(wp.`Thursday`='ALL') + sum(wp.`Friday`='ALL' ) AS COUNT from `workPattern` wp join Employee e on (e.workpatternId = wp.workpatternId); SELECT e.empId, SUM(wp.monday = 'ALL' + wp.tuesday = 'ALL' + wp.wednesday = 'ALL' + wp.thursday = 'ALL' + wp.friday = 'ALL' + wp.saturday = 'ALL' + wp.sunday = 'ALL' ) cnt FROM workPattern wp INNER JOIN Employee e on e.workpatternId = wp.workpatternId WHERE e.empId = 1;
COUNT
5
empId
cnt
1
1