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Sakila
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AdventureWorks
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AdventureWorks
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WITH t AS ( SELECT 1 AS id UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 10 UNION ALL SELECT 100 UNION ALL SELECT 100 UNION ALL SELECT 500 ) SELECT id, RANK() OVER (ORDER BY id) rnk, (SELECT COUNT(*) + 1 FROM t t2 WHERE t2.id < t1.id) rnk2 FROM t t1 ORDER BY id;
id
rnk
rnk2
1
1
1
1
1
1
1
1
1
10
4
4
100
5
5
100
5
5
500
7
7