add batch
remove batch
split batch
comment selection
show hidden batches
hide batch
highlight batch
db<>fiddle
Db2
Firebird
MariaDB
MySQL
Node.js
Oracle
Postgres
SQL Server
SQLite
TimescaleDB
YugabyteDB
Developer-C 11.1
3.0
4.0
10.2
10.3
10.4
10.5
10.6
10.7
10.8
10.9
5.5
5.6
5.7
8.0
18
11g Release 2
18c
21c
23c
8.4
9.3
9.4
9.5
9.6
10
11
12
13
14
15
16
2012
2014
2016
2017
2017 (Linux)
2019
2019 (Linux)
2022
3.8
3.16
3.27
3.39
2.11
2.14
2.6
2.8
2.18
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
Sakila
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
AdventureWorks
no sample DB
no sample DB
AdventureWorks
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
run
markdown
donate
feedback
about
By using db<>fiddle, you agree to license everything you submit by
Creative Commons CC0
.
--這是我初期設定 declare @basedate date = '2019/5/21'; declare @Setdate date = '2019/5/28'; declare @n int = 5; declare @addDay int = @n - (datediff(day,@basedate,@Setdate)) % ( @n ); --藉由日期間隔 - (輸入日期與基本日期天數差 Mod 日期間隔) 得出與下一個日期天數差 select @addDay diffDay,dateadd(day,@addDay,@Setdate) as CheckDay --輸入日期加上前面的天數差得到結果
diffDay
CheckDay
3
2019-05-31
--這是我初期設定 declare @basedate date = '2019/5/21'; declare @Setdate date = '2019/5/31'; declare @n int = 5; declare @addDay int = @n - (datediff(day,@basedate,@Setdate)) % ( @n ); --藉由日期間隔 - (輸入日期與基本日期天數差 Mod 日期間隔) 得出與下一個日期天數差 select @addDay diffDay,dateadd(day,@addDay,@Setdate) as CheckDay --輸入日期加上前面的天數差得到結果
diffDay
CheckDay
5
2019-06-05