MySQL 8.0

By using db<>fiddle, you agree to license everything you submit by Creative Commons CC0.

CREATE TABLE `_loans` (
  `loan_id` int(11) NOT NULL,
  `price` float(7,2) NOT NULL,
  `term` int(11) NOT NULL,
  `app_date` date NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
INSERT INTO `_loans` (`loan_id`, `price`, `term`, `app_date`) VALUES
(1, 299.00, 24, '2019-01-23'),
(2, 774.00, 24, '2019-01-24'),
(3, 817.80, 24, '2019-01-24'),
(4, 279.99, 24, '2019-01-28'),
(5, 463.99, 24, '2019-01-28'),
(6, 0.00, 24, '2019-01-28'),
(7, 357.00, 24, '2019-02-02'),
(8, 386.98, 24, '2019-02-04'),
(9, 846.00, 24, '2019-02-04'),
(10, 713.99, 24, '2019-02-06'),
(11, 0.00, 24, '2019-02-07'),
(12, 579.00, 24, '2019-02-11'),
(13, 179.00, 24, '2019-02-13'),
(14, 0.00, 24, '2019-02-19'),
(15, 259.00, 24, '2019-02-21'),
(16, 249.99, 24, '2019-02-26'),
(17, 319.00, 24, '2019-03-02'),
(18, 1108.99, 24, '2019-03-05'),
(19, 319.00, 24, '2019-03-05'),
(20, 199.97, 24, '2019-03-06');
ALTER TABLE `_loans`
  ADD PRIMARY KEY (`loan_id`),
  ADD KEY `app_date` (`app_date`);
SELECT monthname as month, year, contracts, totals,
       @running_total := @running_total + totals AS running_totals
FROM (SELECT 
          MONTHNAME(w.app_date) monthname,
          MONTH(w.app_date) monthnum,
          YEAR(w.app_date) year,
          COUNT(*) contracts,
          SUM(w.total_price) totals
      FROM (SELECT 
                app_date,
                SUM(price * term) total_price
                FROM _loans l
                GROUP BY l.loan_id
      ) w
      GROUP BY year, monthnum, monthname
) t
JOIN (SELECT @running_total := 0) r
ORDER BY year, monthnum ASC


month
year
contracts
totals
running_totals


January
2019
6
63234.72
63234.71923828125

February
2019
10
85703.04
148937.75939941406

March
2019
4
46727.04
195664.79919433594

month	year	contracts	totals	running_totals
January	2019	6	63234.72	63234.71923828125
February	2019	10	85703.04	148937.75939941406
March	2019	4	46727.04	195664.79919433594