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Developer-C 11.1
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with t0 as ( select '1@apple@1' as value from dual union all select '2@apple@2' from dual union all select '3@apple@4' from dual union all select '4@box@4' from dual union all select '5@box@5' from dual ), trimmed as ( select regexp_replace(value,'[0-9]*@(.+?)@[0-9]*','\1') as name from t0 ) select name, count(*) from trimmed group by name order by name
NAME
COUNT(*)
apple
3
box
2