SQL Server 2019

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select len('2346789abcdefghjkmnpqrtuvwxyz')

(No column name)

29

select concat(substring(c.chars, (v.n / power(len(c.chars), 5)) % len(c.chars) + 1, 1),
              substring(c.chars, (v.n / power(len(c.chars), 4)) % len(c.chars) + 1, 1),
              substring(c.chars, (v.n / power(len(c.chars), 3)) % len(c.chars) + 1, 1),
              substring(c.chars, (v.n / power(len(c.chars), 2)) % len(c.chars) + 1, 1),
              substring(c.chars, (v.n / power(len(c.chars), 1)) % len(c.chars) + 1, 1),
              substring(c.chars, (v.n / power(len(c.chars), 0)) % len(c.chars) + 1, 1)
             )
from (values (0), (1), (100), (1000), (10000), (100000), (1000000), (10000000), (100000000)) v(n) cross join
     (values ('2346789abcdefghjkmnpqrtuvwxyz')) c(chars)

(No column name)

222222

222223

22226g

22238h

222ewv

2274xb

23f23t

2h72mm

7we93w

select concat(substring(c.chars, (v.n * 1000117 / power(len(c.chars), 5)) % len(c.chars) + 1, 1),
              substring(c.chars, (v.n * 1000117 / power(len(c.chars), 4)) % len(c.chars) + 1, 1),
              substring(c.chars, (v.n * 1000117 / power(len(c.chars), 3)) % len(c.chars) + 1, 1),
              substring(c.chars, (v.n * 1000117 / power(len(c.chars), 2)) % len(c.chars) + 1, 1),
              substring(c.chars, (v.n * 1000117 / power(len(c.chars), 1)) % len(c.chars) + 1, 1),
              substring(c.chars, (v.n * 1000117 / power(len(c.chars), 0)) % len(c.chars) + 1, 1)
             )
from (values (cast(0 as bigint)), (1), (100), (1000), (10000), (100000), (1000000), (10000000), (100000000)) v(n) cross join
     (values ('2346789abcdefghjkmnpqrtuvwxyz')) c(chars)

(No column name)

222222

23f28u

7wepzc

pt2wt6

umbwn3

6z3v9d

dpnd8g

ptchwh

uqb6tv