add batch
remove batch
split batch
comment selection
show hidden batches
hide batch
highlight batch
db<>fiddle
Db2
Firebird
MariaDB
MySQL
Node.js
Oracle
Postgres
SQL Server
SQLite
TimescaleDB
YugabyteDB
Developer-C 11.1
3.0
4.0
10.2
10.3
10.4
10.5
10.6
10.7
10.8
10.9
10.11
11.4
5.5
5.6
5.7
8.0
8.4
18
11g Release 2
18c
21c
23c
8.4
9.3
9.4
9.5
9.6
10
11
12
13
14
15
16
17
2012
2014
2016
2017
2017 (Linux)
2019
2019 (Linux)
2022
3.8
3.16
3.27
3.39
2.11
2.14
2.6
2.8
2.18
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
Sakila
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
AdventureWorks
no sample DB
no sample DB
AdventureWorks
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
no sample DB
run
abort
markdown
donate
feedback
about
By using db<>fiddle, you agree to license everything you submit by
Creative Commons CC0
.
DROP TABLE IF EXISTS yourTable; CREATE TABLE yourTable (crm_id varchar(55), customer_id int); INSERT INTO yourTable (crm_id, customer_id) VALUES ('jon', 12345), ('jon', 12346), ('ben', 12347), ('sam', 12348); SELECT cnt AS crm_id_cnt, COUNT(*) AS num_customer_ids FROM ( SELECT crm_id, COUNT(DISTINCT customer_id) AS cnt FROM yourTable GROUP BY crm_id ) t GROUP BY cnt;
Records: 4 Duplicates: 0 Warnings: 0
crm_id_cnt
num_customer_ids
1
2
2
1