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CREATE TABLE #employee(ID INT IDENTITY(1,1), EmployeeName NVARCHAR(100));

INSERT INTO #employee VALUES (N'waidаnde');


SELECT *
FROM #employee
WHERE EmployeeName LIKE '%waidande%';

SELECT *
FROM #employee
WHERE CAST(EmployeeName AS VARCHAR(100)) <> EmployeeName;
ID EmployeeName
ID EmployeeName
1 waidаnde