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2025.2 LTS
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AdventureWorks
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AdventureWorks
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select str, replace((regexp_match(str, '^[0-9]+,*[0-9]*'))[1], ',', '.') from (values ('1,2TEST'), ('1,2,3'), ('1,2%')) v(str)
str
replace
1,2TEST
1.2
1,2,3
1.2
1,2%
1.2