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with t0 as ( select '1@apple@1' as value union all select '2@apple@2' union all select '3@apple@4' union all select '4@box@4' union all select '5@box@5' ), trimmed as ( select regexp_replace(value,'[0-9]*@(.+?)@[0-9]*','$1') as name from t0 ) select name, count(*) from trimmed group by name order by name
name
count(*)
apple
3
box
2