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Developer-C 11.1
3.0
4.0
10.2
10.3
10.4
10.5
10.6
10.7
10.8
10.9
10.11
11.4
5.5
5.6
5.7
8.0
8.4
18
11g Release 2
18c
21c
23c
8.4
9.3
9.4
9.5
9.6
10
11
12
13
14
15
16
17
2012
2014
2016
2017
2017 (Linux)
2019
2019 (Linux)
2022
3.8
3.16
3.27
3.39
2.11
2.14
2.6
2.8
2.18
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Sakila
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AdventureWorks
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CREATE TABLE t1( IND_REF int, Code int ); insert into t1 values (86034,3299); CREATE TABLE t2( IND_REF int, Code int ); insert into t2 values (86034,1212); insert into t2 (IND_REF,Code) SELECT IND_REF,Code FROM t1 WHERE NOT exists ( SELECT IND_REF,Code FROM t2 where t1.IND_REF = t2.IND_REF and t1.Code = t2.Code ) select * from t2
IND_REF
Code
86034
1212
86034
3299