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create table mytable ( customer_id int, login date ); insert into mytable values (1, '2016-03-01'), (1, '2016-03-02'), (1, '2016-03-03'), (1, '2016-03-05'), (1, '2016-03-06'), (1, '2016-03-07'), (1, '2016-03-08');
7 rows affected
WITH cte AS ( select *, CASE WHEN DATEDIFF(DAY, login, LEAD(login, 1, login) over (PARTITION BY customer_id ORDER BY login)) = 1 THEN 1 ELSE 0 END AS day_diff from mytable ), cte2 as ( SELECT *, row_number() over (partition by customer_id order by login) - sum(day_diff) over (partition by customer_id, day_diff order by login) AS grp FROM cte ), cte3 AS ( SELECT customer_id, grp, COUNT(1) AS consecutive_day FROM cte2 GROUP BY customer_id, grp ) SELECT customer_id, MAX(consecutive_day) AS highest_consecutive_day FROM cte3 GROUP BY customer_id
customer_id
highest_consecutive_day
1
3