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10
11
12
13
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15
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19 beta 3
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2024.2 LTS
2025.2 LTS
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Sakila
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AdventureWorks
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AdventureWorks
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WITH yourTable AS ( SELECT '01' AS id, 'admin 2024-03-01' AS user_type UNION ALL SELECT '02', 'admin 2024-03-01' UNION ALL SELECT '03', 'user 2024-03-02' UNION ALL SELECT '04', 'user 2024-03-02' UNION ALL SELECT '05', 'premium_user 2024-03-03' ) SELECT SUBSTRING(user_type from '^\w+') AS user_type, COUNT(*) AS count FROM yourTable GROUP BY user_type ORDER BY COUNT(*) DESC;
user_type
count
admin
2
user
2
premium_user
1
SELECT 3