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Developer-C 11.1
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CREATE TABLE Strings( Str VARCHAR(45) ); INSERT INTO Strings VALUES ('abc@gmail.com'), ('pqr@yahoo.com'), ('mnz@hotmail.com'); UPDATE S SET S.Str = REPLACE(S.Str, E.V, '@outlook.com') FROM Strings S JOIN (VALUES('@gmail.com'), ('@hotmail.com'), ('@yahoo.com')) E(V) ON S.Str LIKE CONCAT('%', E.V, '%'); SELECT * FROM Strings;
Str
abc@outlook.com
pqr@outlook.com
mnz@outlook.com