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Developer-C 11.1
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DECLARE @Temp TABLE ( id int, userid int, result varchar(4) ) INSERT INTO @Temp (id, userid, result) VALUES (1, 1, 'win'), (2, 1, 'loss'), (3, 1, 'win'), (4, 1, 'win'), (5, 2, 'win'), (6, 1, 'loss'), (7, 2, 'win'), (8, 1, 'loss'), (9, 2, 'win'), (10, 3, 'win'), (11, 2, 'loss'), (12, 2, 'loss'), (13, 2, 'loss'), (14, 3, 'win'), (15, 3, 'win'), (16, 1, 'win'), (17, 1, 'win'), (18, 2, 'win') ; --先找出非此場同玩家不同結果的數量 with STEP1 as ( SELECT A.*, ( SELECT COUNT(B.id) FROM @Temp AS B WHERE B.userid=A.userid AND B.id < A.id AND B.result<>A.result ) AS flag FROM @Temp AS A ) --接著以玩家、結果、跟上一步取得的數量分組 --得出連勝輸數量 , STEP2 as ( SELECT A.userid, A.result, A.flag, COUNT(A.userid) AS recode FROM STEP1 AS A GROUP BY A.userid, A.result, A.flag ) --找出連勝輸數量大於1的就可以得到期望的結果 SELECT A.userid, A.result, A.recode FROM STEP2 AS A WHERE A.recode > 1 ORDER BY A.userid, A.flag;
userid
result
recode
1
win
2
1
loss
2
1
win
2
2
win
3
2
loss
3
3
win
3