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declare @now date = '2020-2-3'; --以今天為基準 --統計13號出現在星期幾的總數 with cte as ( select datepart(dw, convert(nvarchar(8),dateadd(month,val,dateadd(year,-400,@now)),121) + '13') week from ( --藉由spt_values + cross join得到多rows資料 select row_number() over (order by(select 1)) - 1 val from master..spt_values T1,master..spt_values T2 where t1.type = 'P' ) T where val <= 800 * 12 - 1 ) select week dow ,count(1) count from cte group by week order by dow;
dow
count
1
1374
2
1370
3
1370
4
1374
5
1368
6
1376
7
1368